F=0.02x^2+17

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Solution for F=0.02x^2+17 equation: 



=0.02F^2+17

We move all terms to the left:

-(0.02F^2+17)=0

We get rid of parentheses

-0.02F^2-17=0

a = -0.02; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·(-0.02)·(-17)
Δ = -1.36
Delta is less than zero, so there is no solution for the equation

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